Question 1171273



It appears that all even squares - except {{{1}}} -  will terminate in the 1st column

The next perfect square after {{{12000}}} is {{{12100}}}

The square root of {{{12100 }}}is {{{110}}}

So, we will have a square that will have {{{110}}} integers on each side

{{{12100 }}}will be in the {{{1st}}} column.....

{{{12109}}} will be in the second column = {{{12100 - 12109 + 1 = 2}}}

{{{12108}}} will be in the 3rd column = {{{12100 - 12108 + 1 = 3}}}


So, to find the column containing {{{12000}}} we can evaluate this

{{{12100 - 12000 + 1 }}} =

{{{100 + 1 }}} =

{{{101 }}}

Answer: C) {{{101}}}

The number {{{12000}}} will be in column {{{101}}} (and row {{{110}}}).