Question 1171274
Determine the equation of the quadratic given roots-1/3, -2/5
The answer must be in the form ax^2+bx+c=0
:
We got
x = - 1/3
3x = -1
3x + 1 = 0
and
x = -2/5
5x = -2
5x + 2 = 0
FOIL (3x+1)(5x+2)
15x^2 + 6x + 5x + 2 = 0
15x^2 + 11x + 2 = 0 is what I get