Question 1171235
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Let *[tex \Large x] represent the amount he started with.


If he spent *[tex \Large \frac{1}{4}] plus $10 on books, then after he bought the books but before he bought the DVDs he would have:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ \(\frac{1}{4}x\,+\,10\)]


left.  Let *[tex \Large u] represent that amount, to wit:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ u\ =\ x\ -\ \(\frac{1}{4}x\,+\,10\)]


Having *[tex \Large u] dollars left, he then went DVD shopping, so at the end of that transaction he had:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ u\ -\ \(\frac{2}{5}u\,+\,8\)\ =\ 130]


Solve for *[tex \Large u] and then use that value to solve for *[tex \Large x]

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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