Question 1171227
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We have 4 red, 2 green and 5 orange.
This leads to a total of 4+2+5 = 6+5 = 11.


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Part (a)


There are 2 green out of 11 total. The probability of getting green is 2/11.


Answer: 2/11

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Part (b)


There are 4 red and 5 orange, so 4+5 = 9 are not green.
The probability of not green is 9/11.


Note how 2/11 from part (a) adds to 9/11 to get 11/11 = 1.
So you could do 1 - (2/11) = 9/11.


Answer: 9/11

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Part (c)


There are 5 orange out of 11 total. So we get 5/11 as the theoretical probability of randomly selecting an orange ball.


Answer: 5/11
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Part (d)


P(orange) = probability of orange
P(not orange) = probability of not orange
P(orange)+P(not orange) = 1
P(not orange) = 1 - P(orange)
P(not orange) = 1 - (5/11)
P(not orange) = (11/11) - (5/11)
P(not orange) = (11-5)/11
P(not orange) = 6/11
Or we could note there are 4 red and 2 green, so 4+2 = 6 non orange balls out of 11 total.
This probability is complementary to the result from part (c).


Answer: 6/11
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