Question 1171114

let one number be {{{x}}} and other number {{{y}}}

a number is added to a number the answer is {{{20}}}, we have

{{{x+y=20}}}.......solve for {{{x}}}

{{{x=20-y}}}.....eq.1


if the difference between the numbers is {{{4}}}, we have

{{{x-y=4}}}..........eq.2, substitute {{{x}}} from eq.1

{{{20-y-y=4}}}

{{{20-2y=4}}}

{{{20-4=2y}}}

{{{16=2y}}}

{{{y=8}}}

go to

{{{x=20-y}}}.....eq.1, substitute {{{y}}}

{{{x=20-8}}}

{{{x=12}}}


your numbers are: {{{8}}} and {{{12}}}