Question 1171029
Just simply rewrite the given equation to its standard form of quadratic equation  then find the value of a, b and c
x/(x-5) - 3/(x+1) = 30/(x2-4x-5)
<pre>{{{system(matrix(3,3, x/(x - 5) - 3/(x + 1), "=", 30/(x^2 - 4x - 5), x(x + 1) - 3(x - 5), "=", 30, x^2 + x - 3x + 15, "=", 30), highlight(matrix(1,3, x^2 - 2x - 15, "=", 0)))}}}
Correct answer: Compare the above to {{{matrix(1,3, ax^2 + bx + c, "=", 0)}}}, and you'll see that: {{{highlight_green(matrix(3,3, a, "=", 1, b, "=", - 2, c, "=", - 15))}}}