Question 1171073
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If a total of *[tex \Large P] monetary units is invested in two different accounts paying *[tex \Large i_1] percent and *[tex \Large i_2] simple interest respectively and *[tex \Large x] is the amount invested in one of the accounts, the total amount of interest earned in a year in the two accounts is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{i_1}{100}x\ +\ \frac{i_2}{100}\(P\,-\,x\)]


Set this equal to the total amount of interest earned, solve for *[tex \Large x] and then calculate *[tex \Large P\,-\,x]

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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