Question 1171044
.
<pre>

Use the basic formula for accounts compounded continuously


    35000 = {{{10000*e^(0.09*t)}}}.


In this equation t is the unknown time in years.


    {{{35000/10000}}} = {{{e^(0.09*t)}}}


    3.5 = {{{e^(0.09*t)}}}


Take the natural logarithm of both sides


    ln(3.5) = 0.09*t


    t = {{{ln(3.5)/0.09}}} = 13.92.


<U>ANSWER</U>.  In 13.92 years. 
</pre>


Solved.


-------------------


To see many other similar solved problems, look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/logarithm/Problems-on-continuously-compound-accounts.lesson>Problems on continuously compounded accounts</A> 

in this site, and learn the subject from there.



After reading this lesson, you will tackle such problems on your own without asking for help from outside.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic "<U>Logarithms</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.



Happy learning (!)