Question 1170937
your inequality is:


8x + 25y >= 6000


at the point (400,100), x = 400 and y = 100.
8x + 25y >= 6000 becomes:
8*400 + 25*100 >= 6000 which becomes:
3200 + 2500 >= 6000 which becomes:
5700 >= 6000 which is false.


at the point (500,100), x = 500 and y = 100.
8x + 25y >= 6000 becomes:
8*500 + 25*100 >= 6000 which becomes:
4000 + 2500 >= 6000 which becomes:
6500 >= 6000 which is true.


at the point (100,200), x = 100 and y = 200.
8x + 25y >= 6000 becomes:
8*100 + 25*200 >= 6000 which becomes:
800 + 5000 >= 6000 which becomes:
5800 >= 6000 which is false.


the only point that satisfies the inequality is the point (500,100).
the other two points don't satisfy the inequality.


graph the equation of 8x + 25y = 6000
any point below that line does not satisfy the inequality.
any point on or above that line satisfies the inequality.


i graphed the line and plotted the points (400,100), (500,100), (100,200).
only the point (500,100) satisfied the inequality.
the other two points didn't.


this was confirmed by the algebraic solutions that were determined above.


here's the graph.


<img src = "http://theo.x10hosting.com/2020/120302.jpg" >