Question 1170979
The total height will be h0 + h, where h0 is the height of the cliff
We can use the formula v2^2 = v1^2 + 2ah, with v1 = vy = 20*sin(60), and a = g
h = vy^2/2g
I assume total hang time refers to the time the ball takes to hit the ground.
The time to reach maximum height is determined from v2 = v1 + at, 
with v2 = 0. Thus t = vy/g
The time to fall from the maximum height to the ground is determined from
h + h0 = v1t + 1/2at^2.  Since v1 = 0, we have t = sqrt(2(h + h0)/g)
Now for the final velocity, we need to determine the x and y components
vx will remain constant throughout, and is equal to 20*cos(60)
The y component of the final velocity is obtained from v2^2 = v1^2 + 2a(h+h0)
with v1 = 0
I will leave it to you to fill in the values and get the final numbers