Question 1170983
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The ratio of *[tex \Large a] to *[tex \Large b] is the same thing as *[tex \Large \frac{a}{b}] reduced to lowest terms.  Carly is clearly wrong because there are more boys than girls, so the correct answer has to be a ratio where the first number is larger than the second one.  Create the fraction:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \text{\frac{number of boys}{number of girls}}]


reduce to lowest terms and then create the correct ratio:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ n\,:\,d]


Where *[tex \Large n] is the numerator of the reduced fraction and *[tex \Large d] is the denominator.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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