Question 1170905
<pre>
Instead of doing your problem for you, I'll do another one that is exactly like
it step by step.  The problem I'll do for you is this:
</pre>What is the midpoint of the line segment that has one endpoint as (11,-15) and the
other endpoint as (-6,9)?<pre>
First I plot the points and draw the line:
{{{drawing(460,600,-9,14,-18,12,graph(460,600,-9,14,-18,12), line(11,-15,-6,9),
circle(11,-15,.15),circle(-6,9,.15), locate(-5.8,9.6,"(-6,9)"),
locate(11,-15,"(11,-15)")

)}}}  

Average the first coordinates, which are 11 and -6:
Add them (11)+(-6) = 5
Divide by 2.
Get {{{5/2}}}
So {{{5/2}}} is the first coordinate of the midpoint.

Average the second coordinates, which are -15 and 9:
Add them (-15)+(9) = -6
Divide by 2.
Get {{{(-6)/2}}}, which reduces to -3
So {{{-3}}} is the second coordinate of the midpoint.

So {{{(matrix(1,3,5/2,",",-3))}}} is the midpoint of the
line segment.  Let's plot it as a check.  To plot the improper
fraction {{{5/2}}}, we change it to mixed number {{{2&1/2}}}.

{{{drawing(460,600,-9,14,-18,12,graph(460,600,-9,14,-18,12), line(11,-15,-6,9),
circle(11,-15,.15),circle(-6,9,.15), locate(-5.8,9.6,"(-6,9)"),
locate(11,-15,"(11,-15)"),

red(circle(5/2,-3,.22), locate(3.4,-2.1,(matrix(1,3,5/2,",",-3))))

)}}}  

That looks like the midpoint, So I think the correct answer to the problem
I worked is

{{{(matrix(1,3,5/2,",",-3))}}}

Now do your problem exactly the same way step by step.

Edwin</pre>