Question 109129
{{{(8b)^2(2b)^-8*(2b)^6}}}..........substitute {{{(2b)^-8 =1/(2b)^8}}}

 = {{{(8b)^2*(1/(2b)^8)*(2b)^6}}}...here{{{8b}}} we can write as {{{2^3b}}}

 = {{{(2^3b)^2*((2b)^6/(2b)^8)}}}......factor out {{{2^2 = 4}}}

= {{{4(2b)^2*(2b^(6-8))}}}

= {{{4(2b)^2*(2b)^-2}}}

= {{{4(2b)^2/(2b)^2}}}..........cancel {{{(2b)^2}}}

= {{{4}}}