Question 1170845



{{{y=log(a,x)}}}
 
given ({{{4}}},{{{1/2}}})

use given point

{{{1/2=log(a,4)}}}....convert to base {{{10}}}
 
{{{1/2=log(4)/log(a)}}}

{{{(1/2)log(a)=log(4)}}}

{{{log(a^(1/2))=log(4)}}}

{{{log(sqrt(a))=log(4)}}}....if log same then

{{{sqrt(a)=4}}}

{{{(sqrt(a))^2=4^2}}}

{{{a=16}}}

your function is:

{{{y=log(16,x) }}}



{{{drawing( 600, 600, -10,10, -10, 10,
circle(4,1/2,.12),locate(4,1/2,p(4,1/2)),
 graph( 600, 600, -10,10, -10, 10, log(16,x))) }}}