Question 1170800

2y = x + 3

5y = x - 7

What is the solution set of the given system?

{(-29/3, -10/3)}
{(29/3, 10/3)}
{(1/3, 4/3)}
{(-1/3, -4/3)}
<pre>2y = x + 3 ---- eq (i)
5y = x - 7 ---- eq (ii)
3y = - 10 ----- Subtracting eq (i) from eq (ii)
{{{highlight_green(matrix(1,3, y, "=", (- 10)/3))}}}

{{{matrix(1,3, 2((- 10)/3), "=", x + 3)}}} ------- Substituting {{{(- 10)/3}}} for y in eq (i)
{{{highlight_green(matrix(3,3, (- 20)/3, "=", x + 3, (- 20)/3 - 3, "=", x, (- 29)/3, "=", x))}}} 
Solution set: {{{highlight_green(matrix(1,5, "(", (- 29)/3, ",", (- 10)/3, ")"))}}}