Question 1170748

A chemist has three different acid solutions. The first acid solution contains 15% acid, the second contains 35% and the third contains 65%. He wants to use all three solutions to obtain a mixture of 64 liters containing  
45% acid, using 2 times as much of the 65% solution as the 35% solution. How many liters of each solution should be used?
<pre>Let amount of 35% acid to be used be T
Then amount of 65% acid to be used is 2T, and amount of 15% acid to be used is, 64 - (T + 2T) = 64 - 3T
We then get: .35T + .65(2T) + .15(64 - 3T) = .45(64)
.35T + 1.3T + 9.6 - .45T = 28.8
1.2T = 19.2
Amount of 35% acid to be used, or {{{highlight_green(matrix(1,6, T, "=", 19.2/1.2, "=", 16, L))}}}
Amount of 65% acid to be used: {{{highlight_green(matrix(1,4, 2(16), "=", 32, L))}}}
Amount of 15% acid to be used: {{{highlight_green(matrix(1,6, 64 - 3T, "=", 64 - 3(16), "=", 16, L))}}}