Question 1170698
{{{log((x+6)/(x+2))=log(x)}}}


{{{(x+6)/(x+2)=x}}}

{{{x+6=x^2+2x}}}

{{{x^2+2x-x=6}}}

{{{x^2+x=6}}}

{{{x(x+1)=6}}}

{{{__}}}.


<s>Looking at the original equation,  -2 will not work.</s>
{{{cross(x=-3)}}}