Question 1170676


 
given:
A pond is a half acre and is frozen over. 
The depth of ice covering pond is {{{2in}}}. 
Ice weighs {{{57.4lb}}}. per {{{cu. ft}}}.
Half acre = {{{21780ft^2}}}.

we need a volume of ice
{{{2in}}} ocvert to ft: {{{2in=(2/12)ft=(1/6)ft}}}
{{{21780ft^2(1/6)ft=(21780/6)ft^3=3630ft^3}}}


since ice weighs {{{57.4lb/ft^3}}}. per {{{cu. ft}}}, we have

{{{(57.4lb/cross(ft^3))*3630cross(ft^3)=57.4lb*3630=208362lb}}}

 the weight of ice is {{{208362lb}}}