Question 1170560


Solve for {{{Z}}}: 

{{{z+i^3=1/(1-i^2)}}}.......... since {{{i^2=-1}}} and {{{i^3=i^2*i=-1*i=-i}}} 

{{{z-i=1/(1-(-1))}}}

{{{z-i=1/(1+1)}}}

{{{z-i=1/2}}}

{{{z=1/2+i}}}