Question 1170529
<pre>
First way: substitute the 6 consecutive values of i:

{{{sum((2i+1),i=1,6)}}}{{{""=""}}}{{{(2*1+1)+(2*2+1)+(2*3+1)+(2*4+1)+(2*5+1)+(2*6+1)}}}{{{""=""}}}{{{(2+1)+(4+1)+(6+1)+(8+1)+(10+1)+(12+1)}}}{{{""=""}}}{{{3+5+7+9+11+13}}}{{{""=""}}}{{{48}}}

Second way: break the sum into basic sum with formulas:

{{{sum((2i+1),i=1,6)}}}{{{""=""}}}{{{sum((2i),i=1,6)}}}{{{""+""}}}{{{sum((1),i=1,6)}}}{{{""=""}}}{{{2*sum((i),i=1,6)}}}{{{""+""}}}{{{sum((1),i=1,6)}}}{{{""=""}}}{{{2*((6(6+1))/2)}}}{{{""+""}}}{{{6}}}{{{""=""}}}{{{2*(6*7/2)}}}{{{""+""}}}{{{6}}}{{{""=""}}}{{{cross(2)*(6*7/cross(2))}}}{{{""+""}}}{{{6}}}{{{""=""}}}{{{42+6}}}{{{""=""}}}{{{48}}}

Edwin</pre>