Question 1170494
<pre>
The way you wrote it, using no parentheses at all, the PEMDAS rule 
says that you mean this:

{{{1/2+1/8+3/16}}}÷{{{5/8+3/16}}}

where we do the division {{{3/16}}}÷{{{5/8}}} first, then change it
to multiplication by the reciprocal of the second as {{{3/16}}}×{{{8/5}}}
where when we cancel we get {{{3/10}}}
So we replace the {{{3/16}}}÷{{{5/8}}} by {{{3/10}}} and now we have:

{{{1/2+1/8+3/10+3/16}}}

and the LCD is 80, so we have

{{{40/80+10/80+24/80+15/80}}}

We add the numerators and put it over the LCD as

{{{89/80}}} or {{{1&9/80}}}

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But you may have forgotten about parentheses and ignored the PEMDAS rule 
and meant this instead:

{{{(1/2+1/8+3/16)}}}÷{{{(5/8+3/16)}}}

If so we get LCD of 16 on the left and right

{{{(8/16+2/16+3/16)}}}÷{{{(10/16+3/16)}}}

{{{13/16}}}÷{{{13/16}}}

We know that when we divide a number by itself we get 1

or we can invert the second and multiply:

{{{13/16}}}×{{{16/13}}}

and after canceling, we get 1.

So if you ignored PEMDAS and parentheses, the answer is 1.

Edwin</pre>