Question 1170462
..., with current, as it does to travel TWO miles upstream , against current.
<pre>
             SPEED      TIME           DISTANCE

UPSTR        29-c       2/(29-c)          2

DOWNSTR      29+c       3/(29+c)          3
</pre>
{{{2/(29-c)=3/(29+c)}}}

-

{{{2(29+c)=3(29-c)}}}

{{{2*29+2c=3*29-3c}}}

{{{0+2c=29-3c}}}

{{{5c=29}}}

{{{highlight(c=5&4/5)}}}{{{mph}}}