Question 1170400
<br>
{{{2Ax^3-Bx^2-Cx-16 = k(x-1)(x+2)(x-2) = k(x^3-x^2-4x+4)}}}<br>
The constant term is 4k = -16, so k = -4.  Then<br>
{{{2Ax^3-Bx^2-Cx-16 = -4x^3+4x^2+16x-16}}}<br>
Equating coefficients of each terms gives<br>
2A = -4, so A = -2
-B = 4, so B = -4
-C = 16, so C = -16<br>