Question 1170407
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Given A:C = 4:5, let A's portion be 4x and C's portion be 5x.<br>
Then, since B's portion is $5 less than C's, B's portion is 5x-5.<br>
A's portion plus B's portion totaled $35:<br>
{{{4x+(5x-5) = 35}}}<br>
Solve for x using basic algebra; then use that value to determine each portion.<br>
Note the portions don't turn out to be whole numbers, either in dollars or in cents; so I suspect the problem is flawed.<br>