Question 1170387
.
<pre>

Let  "n"  be a natural number the problem asks for.


Then according to the condition, we can write


    n = 7*m + m


where an integer number  "m"  is the quotient and the remainder, at the same time.


As a remainder, the number  "m"  is under  inequalities  0 <= m <= 6;  so "m" may have these and only these values

     m = 0, 1, 2, 3, 4, 5, 6.


Accordingly, the number "n" may have these and only these values


    n = 7*0 + 0 = 0

    n = 7*1 + 1 = 8

    n = 7*2 + 2 = 16

    n = 7*3 + 3 = 24

    n = 7*4 + 4 = 32

    n = 7*5 + 5 = 40

    n = 7*6 + 6 = 48


<U>ANSWER</U>.  The possible values are  0, 8, 16, 24, 32, 40, 48.
</pre>

Solved, answered and explained.  And completed.