Question 1170337
{{{x^2+8x=4-4y}}}
{{{x^2+8x+16=4-4y+16}}}
{{{(x+4)^2=-4y+20}}}
{{{highlight((x+4)^2=-4(y+5))}}}


The equation now shows parabola is concave downward with vertex as maximum point.


------------------
Vertex (-4,-5)
----------------------------------------------------------
Distance between vertex and either focus or directrix is 1.
----------------------------------------------------------
Focus (-4,-6)
--------------------------------------------------------
Directrix  {{{y=-4}}}
---------------------------------------------------------


{{{graph(500,500,-10,4,-10,4,-(1/4)(x+4)^2-5)}}}