Question 1170338
Concave the the right, horizontal symmetry axis, according to the given focus and vertex.


Quick sketch shows distance between vertex and focus is 4.


{{{4p(x-h)=(y-k)^2}}}

{{{4*4(x+3)=(y-1)^2}}}

{{{highlight(16(x+3)=(y-1)^2)}}}



{{{graph(500,500,-9,9,-9,9,1+sqrt(16x+48),1-sqrt(16x+48))}}}
(the skip in the middle is unintended)