Question 1170287
0--0.31---product 0--------------squared deviation*probability=1.12^2*0.31=0.3889
1--0.42-----------0.42-----------0.0144*0.42=0.006048
2--0.21-----------0.42-----------0.88*0.21=0.1848
3--0.04----------0.12------------1.88^2*0.04=0.1414
4--0.04----------0.16------------2.88^2*0.04=0.3318
sum is expected value, and that is 1.12 cups, which is the mean
variance is sum of squared deviations * p(x)=1.0529 cups^2
sd is sqrt(V)=1.026 cups