<PRE><B>Question 1170197</B>
normal speed of bus is 270mi/x where x is number of hours
speed of bus leaving at 6:30  and distance is 270 miles, so speed is 270/x-0.5.
(270/x)+6=270/(x-0.5)
(270+6x)/x=270/(x-0.5)
270x=270x-135+6x^2-3x
0=6x^2-3x-135
0=(x-5)(6x+27)
x=5 hours only positive root
54 mph is normal speed (270/5)
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when the bus goes 60 mph, it takes 4.5 hours,</PRE>