Question 1169998

The problem I got incorrect: 
Find inverse of h(x)=(3/4)x+12
My steps...
1) y = (3/4)x+12
2) (4/3)y = x+12
3) (4/3)y-12 = x
4) (4/3)x-12 = y 
5) h^-1(x) = (4/3)x-12

Am told correct answer should be h^-1(x) = (4/3)(x-12). 
Could someone explain the property I missed applying?  
Thank you.
<pre>Never "trust" any answer the other person gives. In MOST cases, his answers are WRONG!! So, I sympathize with you getting a wrong
answer after determining the inverse, but also getting another wrong answer from someone who claims to be a tutor!
Just "throw" his answer in the GARBAGE, or SIMPLY do this: <s><b>The inverse of h  is  {{{cross((4/3)x+16)}}}</s></b>

Inverse of {{{matrix(1,3, h(x), "=", (3/4)x + 12)}}}
Step 1): {{{matrix(1,3, y, "=", (3/4)x + 12)}}} <==== Correct
Step 2): {{{matrix(1,3, x, "=", (3/4)y + 12)}}} ----- Switching variables
Step 3): {{{matrix(1,3, x - 12, "=", (3/4)y)}}}
Step 4): {{{highlight_green(matrix(1,7, (4/3)(x - 12), "=", y, or, (4/3)x - 16, "=", h^((-1))x)))}}}