Question 1169998
{{{h=(3/4)x+12}}}

this method is crude:
{{{(3/4)y+12=x}}}

{{{(3/4)y=x-12}}}

{{{y=(4/3)(x-12)}}}

{{{y=(4/3)x-16}}}


The inverse of h  is  {{{(4/3)x-16}}}.