Question 1169926

Standard deviation of {{{x }}}={{{ 5}}}

=>{{{delta= 5}}}

We need to find the value of {{{Var((3x+10)/2)=Var((3/2)x+5)}}}

As we know that

{{{Var(ax+b)=x^2*Var(x) }}}


so, our equation becomes,

{{{Var((3/2)x+5)=(3/2)^2*delta^2 }}}

{{{Var((3/2)x+5)=(9/4)*(5)^2 }}}

{{{Var((3/2)x+5)=(9/4)*25}}}

{{{Var((3/2)x+5)=225/4}}}

{{{Var((3/2)x+5)=56.25}}} -> Answer