Question 1169939
By trial-and-error, x=32.  <br>
One way to come to this answer is to set y to 29.  Then for any x > 29 and x < 58, it is trivial that 29 mod x = 29. So all that is needed is to check 29 mod (x/2) to find the value of x/2 that has remainder 13.  For x=32, we get 29 mod 16 = 13, so the answer x=32 works.