Question 109006
{{{(8x^3 - 6x^2 + 2x) / (4x+1)}}}………factor out {{{x}}} in nominator 

{{{x(8x^2 - 6x + 2) / (4x+1)}}}………write {{{6x}}} as {{{2x}}} – {{{8x}}}



x(8x^2 + 2x – 8x + 2)/(4x + 1)….…..group {{{8x^2 + 2x}}} and –{{{ 8x + 2}}}

x((8x^2 + 4x) – (8x + 2))/(4x + 1) here {{{8x^2 + 2x}}} factor out {{{2x}}}, and here -{{{(8x + 2)}}} factor out {{{2}}}

Then we have:

x(2x(4x + 1) – 2(4x + 1))/(4x + 1)..factor out {{{4x+1}}}

{{{x((4x + 1)(2x - 2))/(4x + 1)}}}…..cancel {{{4x+1}}}

{{{x(2x - 2))}}}…..factour out {{{2}}}

{{{2x(x - 1)}}}