Question 1169870
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You need the time value when the function value is maximum.  Since the function is a quadratic with a negative lead coefficient, the graph is a concave down parabola making the vertex of the parabola the point where the value of the function is a maximum.


For any parabola modeled by an equation of the form *[tex \Large y\ =\ ax^2\,+\,bx\,+\,c], the value of the independent variable (*[tex \Large t] for your situation) is found by calculating *[tex \Large \frac{-b}{2a}].


Once you know the value of *[tex \Large t_{max}], then calculate the value of *[tex \Large s\(t_{max}\)]

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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