Question 1169484
z=(x-mean)/sd
or (71-66)/2.5
so the first is the probability z>2 which=0.0228
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middle 40% is between the 30th and 70th percentiles.
from the table or calculator invnorm(.30,0,1) and (.70,0,1) or between-0.5244 nd +0.5244
-0.5244=(x-66)/2.5
x=64.69
and at the upper end 67.31
(64.69, 67.31) inches

P(64.69 inches <X<67.31 inches)=0.40