Question 1169745
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𝑝1 + 3𝑝2 + 3𝑝3 = 32    (1)
𝑝1 + 4𝑝2 + 3𝑝3 = 37    (2)
𝑝1 + 3𝑝2 + 4𝑝3 = 35    (3)


From equation (3), subtract equation (1).  You will get

           p3 = 35 - 32 = 3.    (4)


Next, from equation (2), subtract equation (1).   You will get

     p2       = 37 - 32 = 5.


Sunbstitute the found values  p2= 5,  p3 = 3  into equation (1).  You will get

p1 + 3*5 + 3*3 = 32

which implies  

p1 = 32 - 3*5 - 3*3 = 8.


<U>ANSWER</U>.  p1= 8,  p2= 5,  p3= 3.
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Solved.