Question 1169732


Find the perimeter of a triangle whose vertices are ({{{1}}},{{{4}}}), ({{{5}}},{{{1}}}), ({{{0}}},{{{1}}}).

first find the length of each side

one side: distance between ({{{1}}},{{{4}}}) and ({{{5}}},{{{1}}})

*[invoke formula_distance 1, 4, 5, 1]

side {{{a=5}}}

second side: distance between ({{{1}}},{{{4}}}) and ({{{0}}},{{{1}}})

*[invoke formula_distance 1, 4, 0, 1]

side {{{b=3.16}}}

third side: distance between ({{{0}}},{{{1}}}) and ({{{5}}},{{{1}}})

*[invoke formula_distance 0, 1, 5, 1]

side{{{ c=5}}}

the perimeter of a triangle is: {{{P=a+b+c=5+3.16+5=13.16}}}


answer: 

A.{{{13.16}}}