Question 16310
19-(2x+3)=2(x+3)+x take everthing out of bracket
19-2x+3=2x+6+x without Bracket
+2x+22=2x+6+x Added 19+3
+22=-2x+2x+x move variable to one side
+22=x -2x+2x cancel each other out 

First when you distribute the -1 to (2x+3), they both change to -;
19-2x-3=2(x+3)+x
Now distribute the 2(x+3);
which you did correctly;
so you have:
19-2x-3=2x+6+x
Now move variable to one side and add like terms;
16-6=2x+x+2x
10=5x
Divide by 5;
{{{10/5}}}={{{5x/5}}}
2=x
=)