Question 1169677
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<pre>

Notice that  {{{2048000/1000}}} = 2048 = {{{2^11}}}.



It means that 60 hours = 11 doubling periods.


Hence, one doubling period is  {{{60/11}}} = 5 {{{5/11}}}  hours.


And a quadruple period is twice of it, i.e.  {{{120/11}}} hours = 10 {{{10/11}}} hours.
</pre>

Solved.


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See the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/logarithm/Radioactive-decay-problems.lesson>Radioactive decay problems</A> 

in this site - - - to make your horizon &nbsp;&nbsp;W I D E R.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic "<U>Logarithms</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.