Question 108959
{{{(x^2-2x-35)/(x+5)=((x-7)(x+5))/(x+5)}}}
{{{(x^2-2x-35)/(x+5)=x-7}}}
Yes, you're correct.
You can always check using value for x.
At x=0,
{{{(x^2-2x-35)/(x+5)=(0-0-35)/(0+5)=-7}}}
{{{(x-7)=(0-7)=-7}}}
{{{(x^2-2x-35)/(x+5)=x-7}}}
{{{-7=-7}}}
True statement.