Question 1169616
the slope of a line perpendicular to the slope of another line is the negative reciprocal of the slope of the other line.


therefore, perpendicular lines do not have the same slope.


your selection a is false.


parallel lines do, however, if they have a different y-intercept.


if they have the same slope and the same y-intercept they are identical.


the equation of the line going through the points (3,-9) and (-2,-4) is determined as follows:


the slope intercept form of the equation of a straight line is y = mx + b


m is the slope
b is the y-intercept.


assign (3,-9) to (x1,y1)
assign (-2,-4) to (x2,y2)


equation for the slope is (y2-y1)/(x2-x1).
that becomes (-4--9)/-2-3) which becomes 5/-5 which becomes -1.
the equation becomes y = -1*x + b
solve for b by replacing x and y with the value of one of the points and then solving for b.
i chose (-2,-4)
the equation becomes -4 = -1 * -2 + b
simplify to get -4 = 2 + b
solve for b to get b = -6
the equation becomes y = -x - 6


your selection b is true.


here's the graph of the equation.


<img src = "http://theo.x10hosting.com/2020/111204.jpg">