Question 1169595
in 2005, the sat test had a mean of 520 and a standard deviation of 115.
in 2012, the sat test had a mean of 514 and a standard deviation of 117.
the act test had a mean of 21 and a standard deviation of 5.3.


sat score was 700.
act score was 34.


z-score = (x - m) / s


x is the raw score
m is the mean
s is the standard deviation


for the sat in 2009, z = (700 - 520 / 115 = 1.57


for the sat in 2012, z = (700 - 514) / 117 = 1.59


for the act, z = (34 - 21) / 5.3 = 2.45


the person who took the act test scored significantly better compared to the other people who took the act test.


with a z-score of 1.57, the score was better than 94% of the other people who took the test.


with a z-score of 1.59, the score was better than 94% of the other people who took the test.


with a z-score of 2.45, the score was better than 99% of the people who took the test.


the person who took the act test did better in comparison to the other people who took the act test than the person who took the sat test did in comparison to the other people who took the sat test.