Question 1169526

The difference of three times Faye’s age and four times Joshua’s age is 31. If Faye’s age is five more than twice Joshua’s age, how old is Faye?
<pre>Let Faye's, and Joshua's ages be F and J, respectively
Then we get: 3F + 4J = 31 ------ eq (i)
Also, F = 2J + 5____F - 2J = 5 ------ eq (ii)
Multiply eq (ii) by 2 to get eq (iii), and then add eqs (iii) and (i).
This will ELIMINATE J, or Joshua's age and give you Faye's!