Question 1169474
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<pre>
Let x be the EVEN integer exactly midway between the two odd consecutive integers.


Then the odd integers are (x-1) and (x+1), and


    (x+1)*(x-1) = 323.   or


     x^2 - 1    = 323

     x^2        = 323 + 1 = 324

     x                    = +/- {{{sqrt(324)}}} = +/- 18.


So, the positive odd integers are 17 and 19;

    the negative odd integers are -19 and -17.
</pre>

Solved.


// Solved in a way <U>as it should be done</U>.


// In a way as a good teacher teaches his &nbsp;(or her) &nbsp;good pupils.