Question 1169297
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Solve this quadratic equation


    {{{x^2}}} + {{{8^2}}} = {{{(x+2)^2}}}


    {{{x^2}}} + 64 = {{{x^2 + 4x + 4}}}

                64 = 4x + 4

            64 - 4 = 4x

                60 = 4x

                x = 60/4 = 15.


<U>ANSWER</U>.  The length of the hypotenuse is  (x+2) = 17 cm.

          The legs are 15 cm and 8 cm.
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Solved.