Question 1169205
The x-component of the resultant force is Fx = 450 + 525*cos(40) and 
the y-component is Fy = 525*sin(40)
The magnitude of the resultant force is sqrt(Fx^2 + Fy^2).  
I am getting F = 916.56 N. We must also specify a direction, which is given by
A = arctan(Fy/Fx) = 18.4 deg.