Question 1169114
let the two digits be a & b
then
10a + b = the original number
:
Twice the sum of the digits of a two-digit number is 14.
2(a+b) = 14
simplify divide by 2
a + b = 7
 The original number subtracted from the number formed when the digits are reversed is 27.
(10b + a) - (10a + b) = 27
10b - b + a - 10a = 27
9b - 9a = 27
simplify divide by 9
b - a = 3
:
Use elimination with these two equations
a + b = 7
-a + b = 3
---------------Addition eliminates a, find b
0 + 2b = 10
b = 10/2
b = 5
then
a + 5 = 7
a = 7 - 5
a = 2
:
 What is the original number? 25
:
:
Confirm this in the statement:
"The original number subtracted from the number formed when the digits are reversed is 27."
52 - 25 = 27