<PRE><B>Question 1168957</B>
Jim has one more than twice as many dimes than quarters. he has no other coins.
d = 2q + 1
 If he has $3.25 in change, 
.10d + .25q = 3.25
Replace d with (2q+1)
.10(2q+1) + .25q = 3.25
.20q + .1 + .25q = 3.25
.45q = 3.25 - .10
.45q = 3.25 - .10
q = 3.15/.45
q = 7 quarters
then
d = 2(7) + 1
d = 15 dimes
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Check
.10(15) + .25(7) = 
1.50 + 1.75 = 3.25


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