<PRE><B>Question 1169064</B>
let a = original number in box A
let b = original number in box b
:
1/2 of the sweets in box A were equivalent to 3/8 of the sweets in box B.
{{{1/2}}}*a = {{{3/8}}}*b
multiply both sides by 2
a = {{{6/8}}}*b
which is
a = .75b
:
240 sweets from box B were taken out and box A then had 3 times as many sweets as box B.
a = 3(b-240)
a = 3b - 720
replace a with .75b
.75b = 3b - 720
720 = 3b - .75b
720 = 2.25b
b = 720/2.25
b = 320 sweets originally in B
then
a = .75(320)
a = 240 sweets in A originally
:
:
Check in the 1st equation
{{{1/2}}}*240 = {{{3/8}}}*320
120 = 120



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